Ap Chemistry -- Gravimetric Laboratory

 Ap Biochemistry - Gravimetric Lab Composition

Willy Rupprecht

Date(s) performed: August 2 - 3, 2012

Gravimetric Research of an Unknown Group you Metal Carbonate


The goal of this research laboratory is to determine the personality of a Group 1 material carbonate compound by gravimetric analysis. Process:

The not known carbonate is definitely weighed and then dissolved in water. A simple solution of CaCl2 (calcium chloride) is added to the steel carbonate solution to precipitate the carbonate ions as CaCO3 (calcium carbonate). The precipitate is then blocked, dried, and weighed again. Data:

Equation 1: M2CO3 (s) 2M+ (aq) + CO32- (aq)

Equation two: Ca2+ (aq) + CO32- (aq) CaCO3 (s)

Formula 3: CaCl2 (aq) & M2CO3 (aq) CaCO3 (s) + 2MCl (aq) Mass of Crucible| 25. 721 g

Mass of M2CO3| 2 . 031 g

Mass of Filter Paper| 0. 969 g

Mass of CaCO3| 1 ) 5782 g

Moles of CaCO3| zero. 01577 skin moles

Molar Mass of M2CO3| 128. 79 g/mol

Id of M2CO3| K2CO3 (potassium carbonate)

Percent error| 6th. 8%

Computations and Charts:

Mass of M2CO3

Mass of Crucible and M2CO3 minus Mass of Crucible = mass of M2CO3 twenty-seven. 752 g – 25. 721 g = 2 . 031 g

Mass of CaCO3

Mass of Filtration Paper and CaCO3 minus Mass of Filter Newspaper = Mass of CaCO3

2 . 551 g – 0. 969 g sama dengan 1 . 5782 g

Skin moles of CaCO3

1 . 5782 g CaCO31x 1 mol CaCo3100. '08 g CaCO3 = zero. 01577 mol CaCO3 Large molar Mass with the Unknown Carbonate

2 . 031 g M2CO30. 01577 mol CaCO3 = 128. 79 g/mol M2CO3


By simply filtering and weighing the carbonate after it has brought on, the mass and skin moles of CaCO3 could then be found; with these beliefs, a large molar mass of M2CO3 can be found. Using gravimetric analysis, it has been determined that the unknown Group 1 material carbonate chemical substance is K2CO3 (potassium carbonate). Experimental Causes of Error:

A) The first way to obtain error had to do with the anticipation section of the lab. Not only may be possible, but it is almost guaranteed that the CaCO3 did not precipitate to its maximum extent. Getting a precipitate that is completely pure and is also exactly...



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